2022-06-02 07:11:29 +03:00
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/*
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A V program for Bellman-Ford's single source
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shortest path algorithm.
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literaly adapted from:
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https://www.geeksforgeeks.org/bellman-ford-algorithm-dp-23/
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// Adapted from this site... from C++ and Python codes
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For Portugese reference
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http://rascunhointeligente.blogspot.com/2010/10/o-algoritmo-de-bellman-ford-um.html
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2022-07-01 21:37:00 +03:00
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code by CCS
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2022-06-02 07:11:29 +03:00
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*/
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const large = 999999 // almost inifinity
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// a structure to represent a weighted edge in graph
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struct EDGE {
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mut:
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src int
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dest int
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weight int
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}
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// building a map of with all edges etc of a graph, represented from a matrix adjacency
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// Input: matrix adjacency --> Output: edges list of src, dest and weight
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fn build_map_edges_from_graph<T>(g [][]T) map[T]EDGE {
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n := g.len // TOTAL OF NODES for this graph -- its dimmension
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mut edges_map := map[int]EDGE{} // a graph represented by map of edges
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mut edge := 0 // a counter of edges
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for i in 0 .. n {
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for j in 0 .. n {
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// if exist an arc ... include as new edge
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if g[i][j] != 0 {
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edges_map[edge] = EDGE{i, j, g[i][j]}
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edge++
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}
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}
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}
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// print('${edges_map}')
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return edges_map
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}
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fn print_sol(dist []int) {
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n_vertex := dist.len
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print('\n Vertex Distance from Source')
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for i in 0 .. n_vertex {
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print('\n $i --> ${dist[i]}')
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}
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}
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// The main function that finds shortest distances from src
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// to all other vertices using Bellman-Ford algorithm. The
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// function also detects negative weight cycle
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fn bellman_ford<T>(graph [][]T, src int) {
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mut edges := build_map_edges_from_graph(graph)
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// this function was done to adapt a graph representation
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// by a adjacency matrix, to list of adjacency (using a MAP)
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n_edges := edges.len // number of EDGES
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// Step 1: Initialize distances from src to all other
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// vertices as INFINITE
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n_vertex := graph.len // adjc matrix ... n nodes or vertex
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mut dist := []int{len: n_vertex, init: large} // dist with -1 instead of INIFINITY
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// mut path := []int{len: n , init:-1} // previous node of each shortest paht
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dist[src] = 0
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// Step 2: Relax all edges |V| - 1 times. A simple
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// shortest path from src to any other vertex can have
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// at-most |V| - 1 edges
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for _ in 0 .. n_vertex {
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for j in 0 .. n_edges {
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mut u := edges[j].src
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mut v := edges[j].dest
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mut weight := edges[j].weight
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if (dist[u] != large) && (dist[u] + weight < dist[v]) {
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dist[v] = dist[u] + weight
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}
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}
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}
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// Step 3: check for negative-weight cycles. The above
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// step guarantees shortest distances if graph doesn't
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// contain negative weight cycle. If we get a shorter
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// path, then there is a cycle.
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for j in 0 .. n_vertex {
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mut u := edges[j].src
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mut v := edges[j].dest
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mut weight := edges[j].weight
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if (dist[u] != large) && (dist[u] + weight < dist[v]) {
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print('\n Graph contains negative weight cycle')
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// If negative cycle is detected, simply
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// return or an exit(1)
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return
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}
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}
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print_sol(dist)
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}
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fn main() {
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// adjacency matrix = cost or weight
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graph_01 := [
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[0, -1, 4, 0, 0],
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[0, 0, 3, 2, 2],
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[0, 0, 0, 0, 0],
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[0, 1, 5, 0, 0],
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[0, 0, 0, -3, 0],
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]
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// data from https://www.geeksforgeeks.org/bellman-ford-algorithm-dp-23/
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graph_02 := [
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[0, 2, 0, 6, 0],
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[2, 0, 3, 8, 5],
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[0, 3, 0, 0, 7],
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[6, 8, 0, 0, 9],
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[0, 5, 7, 9, 0],
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]
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// data from https://www.geeksforgeeks.org/prims-minimum-spanning-tree-mst-greedy-algo-5/
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/*
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The graph:
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2 3
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(0)--(1)--(2)
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| / \ |
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6| 8/ \5 |7
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| / \ |
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(3)-------(4)
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9
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*/
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/*
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Let us create following weighted graph
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From https://www.geeksforgeeks.org/kruskals-minimum-spanning-tree-algorithm-greedy-algo-2/?ref=lbp
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10
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0--------1
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| \ |
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6| 5\ |15
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| \ |
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2--------3
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4
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*/
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graph_03 := [
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[0, 10, 6, 5],
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[10, 0, 0, 15],
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[6, 0, 0, 4],
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[5, 15, 4, 0],
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]
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// To find number of coluns
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// mut cols := an_array[0].len
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mut graph := [][]int{} // the graph: adjacency matrix
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// for index, g_value in [graph_01, graph_02, graph_03] {
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for index, g_value in [graph_01, graph_02, graph_03] {
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graph = g_value.clone() // graphs_sample[g].clone() // choice your SAMPLE
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// allways starting by node 0
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start_node := 0
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println('\n\n Graph ${index + 1} using Bellman-Ford algorithm (source node: $start_node)')
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bellman_ford(graph, start_node)
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}
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println('\n BYE -- OK')
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}
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